Street Sense's splits

[the_fat_man]

Originally Posted by Bobby Fischer

i got his 4th qrtr as 24.64
and his final qrtr as 24.61

could well be an error by me or the report

check your beaten lengths.

I show a little bit more than 17 for the 1st call, e.g.
(we are adding HEADS, right?)

[Bobby Fischer]

Originally Posted by the_fat_man

check your beaten lengths.

I show a little bit more than 17 for the 1st call, e.g.
(we are adding HEADS, right?)

here is my math - I am using a new spreadsheet so I a may be in error.

I have 12 beaten lengths for the 3/4 CALL

I have 3.5beaten lengths for the 1M CALL



last 4 furlongs=
=(660*(Q45-R45)+8*AE45)/(X45+0.18*BB45)
=(660feet*(4furlongs)+8feet*12beaten lengths@call)/(51.04seconds+0.18*0beatenlengths@finish)
=53.60502 feet per second
4furlongs or2640 feet/53.60502 feet per second = 49.24912281 seconds



last 2 furlongs=
=(660*(Q45-S45)+8*AF45)/(Y45+0.18*BB45)
=(660feet*(2furlongs)+8feet*3.5beatenlengths@call)/(25.13seconds+0.18*0beatenlengths@finish)
=53.64106645 feet per second
1320 feet/ 53.64106645 = 24.60801187 seconds


last4furlong time 49.24912281 seconds
minus
last 2furlong time 24.60801187 seconds
-------
= 24.64111094 seconds for 6f--->8f

[the_fat_man]

Originally Posted by Bobby Fischer

here is my math - I am using a new spreadsheet so I a may be in error.

I need to recode my program using this algorithm.
Presently using the 6 Ls per second. Not that I pay attention much attention to this. Does it matter?

[blackthroatedwind]

I'm sure I screwed up the math....usually do. I'll take a look after the Sopranos.

[Bobby Fischer]

Originally Posted by the_fat_man

I need to recode my program using this algorithm.
Presently using the 6 Ls per second. Not that I pay attention much attention to this. Does it matter?

now this is really odd -
If I use the traditional method of .2 (or .167) whatever seconds per length and then subtract that from the splits , I get the same answer as the original post (24.21 , 24.43).
- *see work shown below

However if I calculate it by feet per second (velocity) my answer is different.
All im doing with the velocity is saying that street sense ran more feet in the same amount of seconds(faster). The more feet comes from the 3.5 beaten lengths * 8feet in a beaten length(some use 9,10) Then I just went back and divided the total feet in 2 furlongs by the ft/s velocity.

Either I am doing something wrong with my math or their is a funky difference between the methods.




work for traditional math
*last 4 furlongs -
6f--->wire
.2 seconds *12 = 2.4
48.64

24.21



last 2 furlongs
1m ---> wire
.2seconds * 3.5 = .7

25.13 - .7 = 24.43

[ArlJim78]

BTW is right, its Sopranos time.

put away your slide rules and spreadsheets, you'll figure it out later.