![]() |
![]() |
![]() |
|
#1
|
||||
|
||||
![]() Quote:
__________________
Do I think Charity can win? Well, I am walking around in yesterday's suit. |
#2
|
||||
|
||||
![]() This kind of points to what the focus of horseplayers demanding change in the industry should be: MORE ACCURATE TIMING (and thus data) for EVERY HORSE.
There's no excuse for not having a system like Trakus in place for EVERY TRACK. In the meantime, the track heads must be thrilled that the focus of horseplayers is on cheaters. |
#3
|
|||
|
|||
![]() i had also always been told fifths per length-never thought about what that meant for a furlong time.
filing away 1/6th for future reference.
__________________
Books serve to show a man that those original thoughts of his aren't very new at all. Abraham Lincoln |
#4
|
||||
|
||||
![]() a length = 8ft
|
#5
|
||||
|
||||
![]() Quote:
Ok, now I've heard 8, 8.5, 9, and 10 feet are a length. What do chartwriters use as the standard? |
#6
|
||||
|
||||
![]() Quote:
Actually it depends. If they need a horse thats like a length or a 1/2 length or head/neck... it's just by eye. If they are doing a horse thats way off the pace some of them use the rail which is 8feet. Formula Call1 to Call2 (((Call2distance-Call1Distance)*660feet)+LengthsBehindCall1*8-LengthsBehindCall2*8)) / (Call2time-Call1time) Formula Call to finish ((Finishdistance-Call1Distance)*660feet+LengthsBehindCall1*8)/((Finaltime-Call1time)+0.18seconds*BeatenLenghtsFinish) ^^ you get velocity in feet per second if you want it time in Seconds then you divide feet/velocity (#Furlongs*660)/VelocityAnswer 8feet Fontan safety rail .18seconds photo finish tech. |
#7
|
||||
|
||||
![]() Quote:
Sorry for totally derailing this thread. |
#8
|
||||
|
||||
![]() I think the studies that showed it between 8.5 to 9 feet were done by the New Bolton Center, but they are old. Perhaps race horses are getting shorter.
|
![]() |
Thread Tools | |
Display Modes | |
|
|