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  #1  
Old 03-02-2009, 11:38 AM
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Thunder Gulch Thunder Gulch is offline
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Quote:
Originally Posted by The Indomitable DrugS
A 7 point regression is nothing when you're talking about going from like a 100 in a one-turn dirt mile to a 93 in a 9f synthetic route. Especially for a 3yo.

Actually, it might have been a somewhat improved race. He got that big dirt figure while up on a soft pace with an easy trip.
Agree. The surface change is tough to account for nowadays.
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Old 03-02-2009, 12:06 PM
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the_fat_man the_fat_man is offline
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This kind of points to what the focus of horseplayers demanding change in the industry should be: MORE ACCURATE TIMING (and thus data) for EVERY HORSE.

There's no excuse for not having a system like Trakus in place for EVERY TRACK.

In the meantime, the track heads must be thrilled that the focus of horseplayers is on cheaters.
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Old 03-02-2009, 12:08 PM
Danzig Danzig is offline
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i had also always been told fifths per length-never thought about what that meant for a furlong time.
filing away 1/6th for future reference.
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Old 03-02-2009, 12:29 PM
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Bobby Fischer Bobby Fischer is offline
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a length = 8ft
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  #5  
Old 03-02-2009, 12:40 PM
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Quote:
Originally Posted by Bobby Fischer
a length = 8ft

Ok, now I've heard 8, 8.5, 9, and 10 feet are a length. What do chartwriters use as the standard?
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Old 03-02-2009, 12:47 PM
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Bobby Fischer Bobby Fischer is offline
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Quote:
Originally Posted by mes5107
Ok, now I've heard 8, 8.5, 9, and 10 feet are a length. What do chartwriters use as the standard?
8'
Actually it depends. If they need a horse thats like a length or a 1/2 length or head/neck... it's just by eye. If they are doing a horse thats way off the pace some of them use the rail which is 8feet.

Formula Call1 to Call2
(((Call2distance-Call1Distance)*660feet)+LengthsBehindCall1*8-LengthsBehindCall2*8)) / (Call2time-Call1time)


Formula Call to finish
((Finishdistance-Call1Distance)*660feet+LengthsBehindCall1*8)/((Finaltime-Call1time)+0.18seconds*BeatenLenghtsFinish)

^^ you get velocity in feet per second
if you want it time in Seconds then you divide feet/velocity (#Furlongs*660)/VelocityAnswer

8feet Fontan safety rail
.18seconds photo finish tech.
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Old 03-02-2009, 01:07 PM
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mes5107 mes5107 is offline
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Quote:
Originally Posted by Bobby Fischer
.18seconds photo finish tech.
So if a horse finished 10 lengths behind the winner on the chart, he was actually 1.8 seconds behind? I think I get all screwed up because only the winner's time is reported in thoroughbred races, where harness and greyhounds report times for all finishers. In greyhound racing a length is always reported as .07 seconds, so it's not so much a measure of distance as it is time. If thoroughbred racing uses the universal reported of lengths behind winner as .18 sec/length, then that would be a good piece of information for me to know.

Sorry for totally derailing this thread.
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  #8  
Old 03-02-2009, 12:48 PM
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The Indomitable DrugS The Indomitable DrugS is offline
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I think the studies that showed it between 8.5 to 9 feet were done by the New Bolton Center, but they are old. Perhaps race horses are getting shorter.
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